Integrand size = 14, antiderivative size = 111 \[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\frac {3 n^{3/2} \sqrt {\pi } x^{1+m} \left (a x^n\right )^{-\frac {1+m}{n}} \text {erfi}\left (\frac {\sqrt {1+m} \sqrt {\log \left (a x^n\right )}}{\sqrt {n}}\right )}{4 (1+m)^{5/2}}-\frac {3 n x^{1+m} \sqrt {\log \left (a x^n\right )}}{2 (1+m)^2}+\frac {x^{1+m} \log ^{\frac {3}{2}}\left (a x^n\right )}{1+m} \]
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Time = 0.08 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {2342, 2347, 2211, 2235} \[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\frac {3 \sqrt {\pi } n^{3/2} x^{m+1} \left (a x^n\right )^{-\frac {m+1}{n}} \text {erfi}\left (\frac {\sqrt {m+1} \sqrt {\log \left (a x^n\right )}}{\sqrt {n}}\right )}{4 (m+1)^{5/2}}+\frac {x^{m+1} \log ^{\frac {3}{2}}\left (a x^n\right )}{m+1}-\frac {3 n x^{m+1} \sqrt {\log \left (a x^n\right )}}{2 (m+1)^2} \]
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Rule 2211
Rule 2235
Rule 2342
Rule 2347
Rubi steps \begin{align*} \text {integral}& = \frac {x^{1+m} \log ^{\frac {3}{2}}\left (a x^n\right )}{1+m}-\frac {(3 n) \int x^m \sqrt {\log \left (a x^n\right )} \, dx}{2 (1+m)} \\ & = -\frac {3 n x^{1+m} \sqrt {\log \left (a x^n\right )}}{2 (1+m)^2}+\frac {x^{1+m} \log ^{\frac {3}{2}}\left (a x^n\right )}{1+m}+\frac {\left (3 n^2\right ) \int \frac {x^m}{\sqrt {\log \left (a x^n\right )}} \, dx}{4 (1+m)^2} \\ & = -\frac {3 n x^{1+m} \sqrt {\log \left (a x^n\right )}}{2 (1+m)^2}+\frac {x^{1+m} \log ^{\frac {3}{2}}\left (a x^n\right )}{1+m}+\frac {\left (3 n x^{1+m} \left (a x^n\right )^{-\frac {1+m}{n}}\right ) \text {Subst}\left (\int \frac {e^{\frac {(1+m) x}{n}}}{\sqrt {x}} \, dx,x,\log \left (a x^n\right )\right )}{4 (1+m)^2} \\ & = -\frac {3 n x^{1+m} \sqrt {\log \left (a x^n\right )}}{2 (1+m)^2}+\frac {x^{1+m} \log ^{\frac {3}{2}}\left (a x^n\right )}{1+m}+\frac {\left (3 n x^{1+m} \left (a x^n\right )^{-\frac {1+m}{n}}\right ) \text {Subst}\left (\int e^{\frac {(1+m) x^2}{n}} \, dx,x,\sqrt {\log \left (a x^n\right )}\right )}{2 (1+m)^2} \\ & = \frac {3 n^{3/2} \sqrt {\pi } x^{1+m} \left (a x^n\right )^{-\frac {1+m}{n}} \text {erfi}\left (\frac {\sqrt {1+m} \sqrt {\log \left (a x^n\right )}}{\sqrt {n}}\right )}{4 (1+m)^{5/2}}-\frac {3 n x^{1+m} \sqrt {\log \left (a x^n\right )}}{2 (1+m)^2}+\frac {x^{1+m} \log ^{\frac {3}{2}}\left (a x^n\right )}{1+m} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.91 \[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\frac {x^{1+m} \left (3 n^{3/2} \sqrt {\pi } \left (a x^n\right )^{-\frac {1+m}{n}} \text {erfi}\left (\frac {\sqrt {1+m} \sqrt {\log \left (a x^n\right )}}{\sqrt {n}}\right )+2 \sqrt {1+m} \sqrt {\log \left (a x^n\right )} \left (-3 n+2 (1+m) \log \left (a x^n\right )\right )\right )}{4 (1+m)^{5/2}} \]
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\[\int x^{m} \ln \left (a \,x^{n}\right )^{\frac {3}{2}}d x\]
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\[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\int { x^{m} \log \left (a x^{n}\right )^{\frac {3}{2}} \,d x } \]
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\[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\int x^{m} \log {\left (a x^{n} \right )}^{\frac {3}{2}}\, dx \]
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\[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\int { x^{m} \log \left (a x^{n}\right )^{\frac {3}{2}} \,d x } \]
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\[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\int { x^{m} \log \left (a x^{n}\right )^{\frac {3}{2}} \,d x } \]
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Timed out. \[ \int x^m \log ^{\frac {3}{2}}\left (a x^n\right ) \, dx=\int x^m\,{\ln \left (a\,x^n\right )}^{3/2} \,d x \]
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